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Chapter 4

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Chapter 4

Calculus Volume 2Chapter 4

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Chapter 4

Checkpoint

4.2

$5$

4.3

$y = 2x^{2} + 3x + 2$

4.5

$y = \frac{1}{3}x^{3} - 2x^{2} + 3x - 6e^{x} + 14$

4.6

$v(t) = -9.8t$

4.7

4.8

The equilibrium solutions are $y = -2$ and $y = 2.$ For this equation, $y = -2$ is an unstable equilibrium solution, and $y = 2$ is a semi-stable equilibrium solution.

4.9

| $n$ | $x_{n}$ | $y_{n} = y_{n - 1} + hf(x_{n - 1},y_{n - 1})$ |

|------|---------|-----------------------------------------------|

| $0$ | $1$ | $-2$ |

| $1$ | $1.1$ | $y_{1} = y_{0} + hf(x_{0},y_{0}) = -1.5$ |

| $2$ | $1.2$ | $y_{2} = y_{1} + hf(x_{1},y_{1}) = -1.1419$ |

| $3$ | $1.3$ | $y_{3} = y_{2} + hf(x_{2},y_{2}) = -0.8387$ |

| $4$ | $1.4$ | $y_{4} = y_{3} + hf(x_{3},y_{3}) = -0.5487$ |

| $5$ | $1.5$ | $y_{5} = y_{4} + hf(x_{4},y_{4}) = -0.2442$ |

| $6$ | $1.6$ | $y_{6} = y_{5} + hf(x_{5},y_{5}) = 0.0993$ |

| $7$ | $1.7$ | $y_{7} = y_{6} + hf(x_{6},y_{6}) = 0.5099$ |

| $8$ | $1.8$ | $y_{8} = y_{7} + hf(x_{7},y_{7}) = 1.0272$ |

| $9$ | $1.9$ | $y_{9} = y_{8} + hf(x_{8},y_{8}) = 1.7159$ |

| $10$ | $2$ | $y_{10} = y_{9} + hf(x_{9},y_{9}) = 2.6962$ |

4.10

$y = 2 + Ce^{x^{2} + 3x}$

4.11

$y = \frac{4 + 14e^{x^{2} + x}}{1 - 7e^{x^{2} + x}}$

4.12

Initial value problem:

$\frac{du}{dt} = 2.4 - \frac{2u}{25},\quad u(0) = 3$

$\text{Solution:}\ u(t) = 30 - 27e^{\text{−}2t\text{/}25}$

$\text{Concentration:~}30 - 27e^{\frac{- 2\mathit{t}}{25}}$

4.13

1. Initial value problem

$\frac{dT}{dt} = k\left( {T - 70} \right),\quad T(0) = 450$

2. $T(t) = 70 + 380e^{kt}$

3. Approximately $114$ minutes.

4.14

1. $\frac{dP}{dt} = 0.04\left( {1 - \frac{P}{750}} \right),\quad P(0) = 200$

2.

3. $P(t) = \frac{3000e^{.04t}}{11 + 4e^{.04t}}$

4. After $12$ months, the population will be $P(12) \approx 278$ rabbits.

4.15

$y\prime + \frac{15}{x + 3}y = \frac{10x - 20}{x + 3};p(x) = \frac{15}{x + 3}$ and $q(x) = \frac{10x - 20}{x + 3}$

4.16

$y = \frac{x^{3} + x^{2} + C}{x - 2}$

4.17

$y = - 2x - \frac{5}{2} + \frac{1}{2}e^{2x}$

4.18

1. $\begin{array}{rll}

\frac{dv}{dt} & = & {\text{−}v - 9.8} \\

{v(0)} & = & 0

\end{array}$

2. $v(t) = 9.8\left( {e^{\text{−}t} - 1} \right)$

3. $\underset{t\rightarrow\infty}{\text{lim}}v(t) = \underset{t\rightarrow\infty}{\text{lim}}\left( {9.8\left( {e^{\text{−}t} - 1} \right)} \right) = -9.8\ \text{m/s} \approx - 21.922\ \text{mph}$

4.19

Initial-value problem:

$8q^{\prime} + \frac{1}{0.02}q = 20\mspace{2mu}\text{sin}\mspace{2mu} 5t,\quad q(0) = 4$

$q(t) = \frac{10\mspace{2mu}\text{sin}\mspace{2mu} 5t - 8\mspace{2mu}\text{cos}\mspace{2mu} 5t + 172e^{-6.25t}}{41}$

Section 4.1 Exercises

1.

$1$

3.

$3$

5.

$1$

7.

$1$

19.

$y = 4 + \frac{3x^{4}}{4}$

21.

$y = \frac{1}{2}e^{x^{2}}$

23.

$y = 2e^{\text{−}{1\text{/}x}}$

25.

$u = \text{sin}^{-1}\left( e^{-1 + t} \right)$

27.

$y = - \frac{\sqrt{x + 1}}{\sqrt{1 - x}} - 1$

29.

$y = C - x + x\mspace{2mu}\text{ln}\mspace{2mu} x - \text{ln}(\text{cos}\mspace{2mu} x)$

31.

$y = C + \frac{4^{x}}{\text{ln}(4)}$

33.

$y = \frac{2}{3}\sqrt{t^{2} + 16}\left( {t^{2} + 16} \right) + C$

35.

$x = \frac{2}{15}\sqrt{4 + t}\left( {3t^{2} + 4t - 32} \right) + C$

37.

$y = Cx$

39.

$y = 1 - \frac{t^{2}}{2},y = - \frac{t^{2}}{2} - 1$

41.

$y = e^{\text{−}t},y = \text{−}e^{\text{−}t}$

43.

$y = 2\left( {t^{2} + 5} \right),t = 3\sqrt{5}$

45.

$y = 10e^{-2t},t = - \frac{1}{2}\mspace{2mu}\text{ln}\mspace{2mu}\left( \frac{1}{10} \right)$

47.

$y = \frac{1}{4}\left( {41 - e^{-4t}} \right),$ never

49.

Solution changes from increasing to decreasing at $y(0) = 0$

51.

Solution changes from increasing to decreasing at $y(0) = 0$

53.

$v(t) = -32t + a$

55.

$0$ ft/s

57.

$52.354$ meters

59.

$x = 50t - \frac{15}{\pi^{2}}\text{cos}(\pi t) + \frac{3}{\pi^{2}},2$ hours $1$ minute

61.

$y = 4e^{3t}$

63.

$y = 3 - 2t + t^{2}$

65.

$y = \frac{1}{k}\left( {e^{kt} - 1} \right)$ and $y = x$

Section 4.2 Exercises

67.

69.

$y = 0$ is a stable equilibrium

71.

73.

$y = 0$ is a stable equilibrium and $y = 2$ is unstable

75.

General solution is $y = e^{t} + C$.

77.

General solution is $y = e^{t}(t - 1) + C$.

79.

81.

83.

85.

E

87.

A

89.

B

91.

A

93.

C

95.

$2.24,$ exact: $2$

97.

$7.739264,$ exact: $5(e - 1)$

99.

$-0.2535$ exact: $0$

101.

$1.345,$ exact: $\frac{1}{\text{ln}(2)}$

103.

$-4,$ exact: $\text{−}{1\text{/}2}$

105.

107.

$y\prime = 2e^{t^{2}\text{/}2}$

109.

$2$

111.

$3.2756$

113.

$2\sqrt{e}$

| Step Size | Relative Error |

|--------------|----------------|

| $h = 0.1$ | $0.3935$ |

| $h = 0.01$ | $0.06163$ |

| $h = 0.001$ | $0.006612$ |

| $h = 0.0001$ | $0.0006661$ |

115.

117.

$4.0741e^{-10}$

Section 4.3 Exercises

119.

$y = e^{t} - 1$

121.

$y = 1 + Ce^{\text{−}t}$

123.

$y = Cxe^{-1\text{/}x}$

125.

$y = \frac{1}{C - x^{2}}$

127.

$y = - \frac{2}{C + \text{ln}\mspace{2mu} x}$

129.

$y = Ce^{x}\left( {x + 1} \right) + 1$

131.

$y = \text{sin}\left( {\text{ln}\mspace{2mu} t + C} \right)$

133.

$y = \text{−}\text{ln}(e^{\text{−}x})$

135.

$y = \frac{1}{\sqrt{2 - e^{x^{2}}}}$

137.

$y = \text{tanh}^{-1}\left( \frac{x^{2}}{2} \right)$

139.

$x = \text{sin}\left( {1 - t + t\mspace{2mu}\text{ln}\mspace{2mu} t} \right)$

141.

$y = \text{ln}(\text{ln}(5)) - \text{ln}(2 - 5^{x})$

143.

$y = Ce^{-2x} + \frac{1}{2}$

145.

$y = \frac{1}{\sqrt{2}\sqrt{C - e^{x}}}$

147.

$y = Ce^{\text{−}x}x^{x}$

149.

$y = \frac{r}{d}\left( {1 - e^{\text{−}dt}} \right)$

151.

$y(t) = 10 - 9e^{\text{−}{x\text{/}50}}$

153.

$134.3$ kilograms

155.

$720$ seconds

157.

$24$ hours $57$ minutes

159.

$T(t) = 20 + 50e^{-0.125t}$

161.

$T(t) = 20 + 38.5e^{-0.125t}$

163.

$y = \left( {c + \frac{b}{a}} \right)e^{ax} - \frac{b}{a}$

165.

$y(t) = cL + (I - cL)e^{\text{−}{{rt}\text{/}L}}$

167.

$y = 40\left( {1 - e^{-0.1t}} \right),40$ g/cm2

Section 4.4 Exercises

169.

$P = 0$ semi-stable

171.

$P = \frac{10e^{10x}}{e^{10x} + 4}$

173.

$P(t) = \frac{10000e^{0.02t}}{150 + 50e^{0.02t}}$

175.

$69$ hours $5$ minutes

177.

$8$ years $11$ months

179.

181.

$P_{1}$ semi-stable

183.

$P_{2} > 0$ stable

185.

$P_{1} = 0$ is semi-stable

187.

$P(t) = \frac{3500}{\left( {4 + 3e^{- 035t}} \right)}$

189.

191.

$P(t) = \frac{850 + 500e^{0.009t}}{85 + 5e^{0.009t}}$

193.

$13$ years months

195.

197.

$31.465$ days

199.

September $2008$

201.

$\frac{K + T}{2}$

203.

$r = 0.0405$

205.

$\alpha = 0.0081$

207.

Logistic: $361,$ Threshold: $436,$ Gompertz: $309.$

Section 4.5 Exercises

209.

Yes

211.

Yes

213.

$y\prime - x^{3}y = \text{sin}\mspace{2mu} x$

215.

$y\prime + \frac{\left( {3x + 2} \right)}{x}y = \text{−}e^{x}$

217.

$\frac{dy}{dt} - yx\left( {x + 1} \right) = 0$

219.

$e^{(e^{x})}$

221.

$\text{−}\text{ln}\left( {\text{cosh}\mspace{2mu} x} \right)$

223.

$y = Ce^{3x} - \frac{2}{3}$

225.

$y = Cx^{3} + 6x^{2}$

227.

$y = Ce^{x^{2}\text{/}2} - 3$

229.

$y = C\mspace{2mu}\text{tan}\left( \frac{x}{2} \right) - 2x + 4\mspace{2mu}\text{tan}\left( \frac{x}{2} \right)\text{ln}\left( {\text{sin}\left( \frac{x}{2} \right)} \right)$

231.

$y = Cx^{3} - x^{2}$

233.

$y = C{(x + 2)}^{2} + \frac{1}{2}$

235.

$y = \frac{C}{\sqrt{x}} + 2\mspace{2mu}\text{sin}(3t)$

237.

$y = C{(x + 1)}^{3} - x^{2} - 2x - 1$

239.

$y = Ce^{\text{sinh}^{-1}x} - 2$

241.

$y = x + 4e^{–x} - 1$

243.

$y = - \frac{3x}{2}\left( {x^{2} - 1} \right)$

245.

$y = 1 - e^{\text{tan}^{-1}x}$

247.

$y = (x + 2)\text{ln}\mspace{2mu}\left( \frac{x + 2}{2} \right)$

249.

$y = 2e^{2\sqrt{x}} - 2x - 2\sqrt{x} - 1$

251.

$v(t) = \frac{gm}{k}\left( {1 - e^{\text{−}{{kt}\text{/}m}}} \right)$

253.

$40.451$ seconds

255.

$\sqrt{\frac{gm}{k}}$

257.

$y = Ce^{x} - a(x + 1)$

259.

$y = Ce^{x^{2}\text{/}2} - a$

261.

$y = \frac{e^{kt} - e^{t}}{k - 1}$

Review Exercises

263.

F

265.

T

267.

$y(x) = \frac{2^{x}}{\text{ln}(2)} + x\mspace{2mu}\text{cos}^{-1}x - \sqrt{1 - x^{2}} + C$

269.

$y(x) = \text{ln}\left( {C - \text{cos}\mspace{2mu} x} \right)$

271.

$y(x) = e^{e^{C + x}}$

273.

$y(x) = 4 + \frac{3}{2}x^{2} + 2x - \text{sin}\mspace{2mu} x$

275.

$y(x) = - \frac{2}{1 + 3\left( {x^{2} + 2\mspace{2mu}\text{sin}\mspace{2mu} x} \right)}$

277.

$y(x) = -2x^{2} - 2x - \frac{1}{3} - \frac{2}{3}e^{3x}$

279.

$y(x) = Ce^{\text{−}x} + \text{ln}\mspace{2mu} x$

281.

Euler: $0.6939,$ exact solution: $y(x) = \frac{3^{x} - e^{-2x}}{2 + \text{ln}(3)}$

283.

$\frac{40}{49}$ second

285.

$x(t) = 5000 + \frac{245}{9} - \frac{49}{3}t - \frac{245}{9}e^{\text{−}{5\text{/}{3t}}},t = 307.8$ seconds

287.

$T(t) = 200\left( {1 - e^{\text{−}{t\text{/}1000}}} \right)$

289.

$P(t) = \frac{1600000e^{0.02t}}{9840 + 160e^{0.02t}}$

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